Selasa, 06 Oktober 2015

Tugas dasjarkom 1 dan 2

Tugas 1
 Buat Jaringan Komputer seperti gambar di bawah dengan Aplikasi Packet Tracer.




     
 Dengan konfigurasi IP 
  • Subnet IP Address 172.16.X.0 /20, X adalah no urut absen Mahasiswa
  • Masukan Alamat Host IP subnet (network) 1 pada PC0 sampai PC4
  • Masukan Alamat Host IP subnet (network) 2 pada PC5 sampai PC8



Network 1

1. IP PC0 = 172.16.24.1/20
Subnet = 255.255.240.0

2. IP PC1 = 172.16.24.2/20
Subnet = 255.255.240.0

3. IP PC3 = 172.16.24.3/20
Subnet = 255.255.240.0

4. IP PC4 = 172.16.24.4/20
 Subnet = 255.255.240.0
          
Network 2

1. IP PC5 = 172.16.30.1/20
Subnet = 255.255.240.0

2. IP PC6 = 172.16.30.2/20
Subnet = 255.255.240.0

3. IP PC7 = 172.16.30.3/20
Subnet = 255.255.240.0

4. IP PC8 = 172.16.30.4/20
Subnet = 255.255.240.0


Subneting /20 = 255. 255.240.0

11111111.11111111.11110000.00000000

Network           : 24  = 16
Host                  : 212 - 2 = 4094
Blok Subnet      : 256 - 240 = 16


Net ID
Host ID
BC
awal
akhir
172.16.0.0
172.16.0.1
172.16.15.254
172.16.15.255
172.16.16.0
172.16.16.1
172.16.31.254
172.16.31.255
172.16.32.0
172.16.32.1
172.16.47.254
172.16.47.255
172.16.48.0
172.16.48.1
172.16.63.254
172.16.63.255
172.16.64.0
172.16.64.1
172.16.79.254
172.16.79.255
172.16.80.0
172.16.80.1
172.16.95.254
172.16.95.255
172.16.96.0
172.16.96.1
172.16.111.254
172.16.111.255
172.16.112.0
172.16.112.1
172.16.127.254
172.16.127.255
172.16.128.0
172.16.128.1
172.16.143.254
172.16.143.255
172.16.144.0
172.16.144.1
172.16.159.254
172.16.159.255
172.16.160.0
172.16.160.1
172.16.175.254
172.16.175.255
172.16.176.0
172.16.176.1
172.16.191.254
172.16.191.255
172.16.192.0
172.16.192.1
172.16.207.254
172.16.207.255
172.16.208.0
172.16.208.1
172.16.223.254
172.16.223.255
172.16.224.0
172.16.224.1
172.16.239.254
172.16.239.255
172.16.240.0
172.16.240.1
172.16.255.254
172.16.255.255


Tugas 2
Buat Jaringan Komputer seperti gambar di bawah dengan Aplikasi Packet Tracer.




   
Dengan konfigurasi IP  
  • Hitunglah Subnet IP address 10.0.X.0 /16, X adalah no urut absen Mahasiswa
  • Masukan Alamat Host IP subnet (network) 1 pada PC0 sampai PC3 serta Server0
  • Masukan Alamat Host IP subnet (network) 4 pada PC5 sampai PC8 serta Server 1



Network 1

1. IP PC0 = 10.0.24.2/16
Subnet = 255.255.0.0

2. IP PC1 = 10.0.24.3/16
Subnet = 255.255.0.0

3. IP PC2 = 10.0.24.4/16
Subnet = 255.255.0.0

4. IP PC3 = 10.0.24.5/16
Subnet = 255.255.0.0

5. IP Server0 = 10.0.24.1
Subnet = 255.255.0.0

Network 4

1. IP PC5 = 10.3.24.2/16
Subnet = 255.255.0.0

2. IP PC6 = 10.3.24.3/16
Subnet = 255.255.0.0

3. IP PC7 = 10.3.24.4/16
Subnet = 255.255.0.0

4. IP PC8 = 10.3.24.5/16
Subnet = 255.255.0.0

5. IP Server1 = 10.3.24.1
Subnet = 255.255.0.0


Subneting /16 = 255.255.0.0
 111111111.11111111.00000000.00000000
Network = 2= 256
Host = 216 - 2 = 65534
Blok Subnet = 256 - 255 = 1




Net ID
Host ID
BC
awal
akhir
10.0.0.0
10.0.0.1
10.0.255.254
10.0.255.255
10.1.0.0
10.1.0.1
10.1.255.254
10.1.255.255
10.2.0.0
10.2.0.1
10.2.255.254
10.2.255.255
10.3.0.0
10.3.0.1
10.3.255.254
10.3.255.255
10.4.0.0
10.4.0.1
10.4.255.254
10.4.255.255
10.5.0.0
10.5.0.1
10.5.255.254
10.5.255.255
10.6.0.0
10.6.0.1
10.6.255.254
10.6.255.255
…………………………………………………………..s/d……………………………………………………………..
10.255.0.0
10.255.0.1
10.255.255.254
10.255.255.255



 Untuk lebih jelasnya bisa download file paket tracer di bawah ini :


Tugas 1

Tugas 2

Senin, 05 Oktober 2015

Tugas 1.
 Buat Jaringan Komputer seperti gambar di bawah dengan Aplikasi Packet Tracer.


https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEi_oInpvV7JI-Icoqi3zQNMn5Z3O3Cu7CEyxSgJs5z3TaauZ1ng0jDSFLhtlNJCe7wtgr19TOTzHYiISBPfZrPBq2g8Sg8ZzTGlA9xD48Ac-u0H4hvu8FcIFW-KTnR89OPlwIUgji8HiqI/s400/a.png

     
 Dengan konfigurasi IP 
Subnet IP Address 172.16.X.0 /20, X adalah no urut absen Mahasiswa
Masukan Alamat Host IP subnet (network) 1 pada PC0 sampai PC4
 Masukan Alamat Host IP subnet (network) 2 pada PC5 sampai PC8


Network 1

1. IP PC0 = 172.16.24.1/20
Subnet = 255.255.240.0

2. IP PC1 = 172.16.24.2/20
Subnet = 255.255.240.0

3. IP PC3 = 172.16.24.3/20
Subnet = 255.255.240.0

4. IP PC4 = 172.16.24.4/20
 Subnet = 255.255.240.0
          
Network 2

1. IP PC5 = 172.16.30.1/20
Subnet = 255.255.240.0

2. IP PC6 = 172.16.30.2/20
Subnet = 255.255.240.0

3. IP PC7 = 172.16.30.3/20
Subnet = 255.255.240.0

4. IP PC8 = 172.16.30.4/20
Subnet = 255.255.240.0


Subneting /20 = 255. 255.240.0

11111111.11111111.11110000.00000000

Network           : 24  = 16
Host                  : 212 - 2 = 4094
Blok Subnet      : 256 - 240 = 16


Net ID
Host ID
BC
awal
akhir
172.16.0.0
172.16.0.1
172.16.15.254
172.16.15.255
172.16.16.0
172.16.16.1
172.16.31.254
172.16.31.255
172.16.32.0
172.16.32.1
172.16.47.254
172.16.47.255
172.16.48.0
172.16.48.1
172.16.63.254
172.16.63.255
172.16.64.0
172.16.64.1
172.16.79.254
172.16.79.255
172.16.80.0
172.16.80.1
172.16.95.254
172.16.95.255
172.16.96.0
172.16.96.1
172.16.111.254
172.16.111.255
172.16.112.0
172.16.112.1
172.16.127.254
172.16.127.255
172.16.128.0
172.16.128.1
172.16.143.254
172.16.143.255
172.16.144.0
172.16.144.1
172.16.159.254
172.16.159.255
172.16.160.0
172.16.160.1
172.16.175.254
172.16.175.255
172.16.176.0
172.16.176.1
172.16.191.254
172.16.191.255
172.16.192.0
172.16.192.1
172.16.207.254
172.16.207.255
172.16.208.0
172.16.208.1
172.16.223.254
172.16.223.255
172.16.224.0
172.16.224.1
172.16.239.254
172.16.239.255
172.16.240.0
172.16.240.1
172.16.255.254
172.16.255.255


Tugas 2.  Buat Jaringan Komputer seperti gambar di bawah dengan Aplikasi Packet Tracer.



https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhgEASOeclYoa3KnKDQIi3Ye0S02qQnf9XtkrVBgAhyphenhyphenQzvn9jAJa_-__nWdzMj871WsRedHP4O41dUY5pv2hB1Nf5GhOKf28eGpKTHAgSFsmrB0-N6K8-SuCEKPnHKpaTHFR14EDo557rE/s320/b.png
   
Dengan konfigurasi IP  
Hitunglah Subnet IP address 10.0.X.0 /16, X adalah no urut absen Mahasiswa
Masukan Alamat Host IP subnet (network) 1 pada PC0 sampai PC3 serta Server0
 Masukan Alamat Host IP subnet (network) 4 pada PC5 sampai PC8 serta Server 1


Network 1

1. IP PC0 = 10.0.24.2/16
Subnet = 255.255.0.0

2. IP PC1 = 10.0.24.3/16
Subnet = 255.255.0.0

3. IP PC2 = 10.0.24.4/16
Subnet = 255.255.0.0

4. IP PC3 = 10.0.24.5/16
Subnet = 255.255.0.0

5. IP Server0 = 10.0.24.1
Subnet = 255.255.0.0

Network 4

1. IP PC5 = 10.3.24.2/16
Subnet = 255.255.0.0

2. IP PC6 = 10.3.24.3/16
Subnet = 255.255.0.0

3. IP PC7 = 10.3.24.4/16
Subnet = 255.255.0.0

4. IP PC8 = 10.3.24.5/16
Subnet = 255.255.0.0

5. IP Server1 = 10.3.24.1
Subnet = 255.255.0.0


Subneting /16 = 255.255.0.0
 111111111.11111111.00000000.00000000
Network = 2= 256
Host = 216 - 2 = 65534
Blok Subnet = 256 - 255 = 1




















Net ID
Host ID
BC
awal
akhir
10.0.0.0
10.0.0.1
10.0.255.254
10.0.255.255
10.1.0.0
10.1.0.1
10.1.255.254
10.1.255.255
10.2.0.0
10.2.0.1
10.2.255.254
10.2.255.255
10.3.0.0
10.3.0.1
10.3.255.254
10.3.255.255
10.4.0.0
10.4.0.1
10.4.255.254
10.4.255.255
10.5.0.0
10.5.0.1
10.5.255.254
10.5.255.255
10.6.0.0
10.6.0.1
10.6.255.254
10.6.255.255
…………………………………………………………..s/d……………………………………………………………..
10.255.0.0
10.255.0.1
10.255.255.254
10.255.255.255



 Untuk lebih jelasnya bisa download file paket tracer di bawah ini :







Net ID
Host ID
BC


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